Thomas Braibant
2014-10-21 07:49:30 UTC
Hi list,
I am slightly puzzled by a type-error related to first class modules.
I am basically defining two types (see full example below)
```
type t = (module A)
type 'a s = (module A with type I.t = 'a)
```
and I expect a value of type `'a s` can be coerced to a value of type
t. However, this is obviously not the case because I get the following
error message, and I wonder why.
```
(* Error: This expression has type a s = (module A with type I.t = a) *)
(* but an expression was expected of type t = (module A) *)
```
Is there a common pattern to deal with this situation? Any pointers appreciated.
Best,
Thomas
(* Full example *)
module type IN = sig
type t
val of_string : string -> t
val to_string : t -> string
end
module type A = sig
module I : IN
val v : string
end
type t = (module A)
type 'a s = (module A with type I.t = 'a)
let test1 : t -> string = fun (module T) -> T.v
(* let test2 : 'a s -> string = fun (module T) -> T.v
The type of this packed module contains variables:
'a s
*)
let test3 (type a) : a s -> string = fun (module T) -> T.v
let test4 (type a) : a s -> string = fun t -> test1 t
(* Error: This expression has type a s = (module A with type I.t = a) *)
(* but an expression was expected of type t = (module A) *)
module A1 : A = struct
module I : IN = struct
type t = int
let of_string = int_of_string
let to_string = string_of_int
end
let v = "A1"
end
let _ = test1 (module A1) (* OK *)
let _ = test3 (module A1) (* OK *)
I am slightly puzzled by a type-error related to first class modules.
I am basically defining two types (see full example below)
```
type t = (module A)
type 'a s = (module A with type I.t = 'a)
```
and I expect a value of type `'a s` can be coerced to a value of type
t. However, this is obviously not the case because I get the following
error message, and I wonder why.
```
(* Error: This expression has type a s = (module A with type I.t = a) *)
(* but an expression was expected of type t = (module A) *)
```
Is there a common pattern to deal with this situation? Any pointers appreciated.
Best,
Thomas
(* Full example *)
module type IN = sig
type t
val of_string : string -> t
val to_string : t -> string
end
module type A = sig
module I : IN
val v : string
end
type t = (module A)
type 'a s = (module A with type I.t = 'a)
let test1 : t -> string = fun (module T) -> T.v
(* let test2 : 'a s -> string = fun (module T) -> T.v
The type of this packed module contains variables:
'a s
*)
let test3 (type a) : a s -> string = fun (module T) -> T.v
let test4 (type a) : a s -> string = fun t -> test1 t
(* Error: This expression has type a s = (module A with type I.t = a) *)
(* but an expression was expected of type t = (module A) *)
module A1 : A = struct
module I : IN = struct
type t = int
let of_string = int_of_string
let to_string = string_of_int
end
let v = "A1"
end
let _ = test1 (module A1) (* OK *)
let _ = test3 (module A1) (* OK *)
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